Asked by Ginny
How do I find the domain of the funcition algebraically and support my answer graphically?
f(x) = sqrt(x2) + (4)
f(x) = sqrt(x2) + (4)
Answers
Answered by
drwls
sqrt (x^2) = x, so I assume you meant to write
f(x) = sqrt(x^2 +4)
The quantity in ( ) is always positive, so there is always a real square root, regardless of the value of x.
The domain is all positive and negative real numbers.
f(x) = sqrt(x^2 +4)
The quantity in ( ) is always positive, so there is always a real square root, regardless of the value of x.
The domain is all positive and negative real numbers.
Answered by
Joseph
please help me with this problem? I have the answer but I need to know how to do it.
Use the point on the line and the slope of the line to find three additional points through which the line passes
point slope
((7,-2) m= 1/2
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