Asked by Maria
(3,5) 2x+y=3 .Write an equation of the line containing the given point and perpendicular to the given line. Express your answer in the form y=mx+b
Answers
Answered by
Damon
re-write your equation in form y = m x + b
y = -2 x + 3
that means the slope m of the original line is -2
the slope of the perpendicular m' is -1/m so
m' = -1/-2 = 1/2
so
y = (1/2) x + b'
now put the point in
5 = (1/2) 3 + b'
b' = 7/2
so
y = x/2 + 7/2
or
2y = x+7
y = -2 x + 3
that means the slope m of the original line is -2
the slope of the perpendicular m' is -1/m so
m' = -1/-2 = 1/2
so
y = (1/2) x + b'
now put the point in
5 = (1/2) 3 + b'
b' = 7/2
so
y = x/2 + 7/2
or
2y = x+7
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