Asked by Michelle
Hydrogen cyanide gas is produced industrially by the reaction
2 CH4(g) + 3 O2(g) + 2 NH3(g) → 2 HCN(g) + 6 H2O(g)
What volume of O2(g) is needed to completely react 17 L of CH4(g) at STP?
2 CH4(g) + 3 O2(g) + 2 NH3(g) → 2 HCN(g) + 6 H2O(g)
What volume of O2(g) is needed to completely react 17 L of CH4(g) at STP?
Answers
Answered by
DrBob222
When one has gases one may treat L as if they were moles and not go through the conversion to mols step.
17 L CH4 x (3 mols O2/2 mols CH4) = 17 x 3/2 = ? L O2.
17 L CH4 x (3 mols O2/2 mols CH4) = 17 x 3/2 = ? L O2.