Question
Water is taken from a well 11m deep in a bucket,the rope winding up to a drum 35cm in diameter.
A)Through what angle does the handle turn in winding up 1m of rope?
B)How many revolutions of the handle does it take to bring the bucket up from the bottom?
C)If the arm of the handle is 42cm long,how far does the hand of the winder travel when bringing the bucket up from the bottom?
My solution so far.
A)1m=100cm
100=tita/360*2*22/7*35/2
tita=327 3/11degree
B) 1rev=360 degree
xrev=327 3/11
=10rev.
Pls kindly help me with the part C
A)Through what angle does the handle turn in winding up 1m of rope?
B)How many revolutions of the handle does it take to bring the bucket up from the bottom?
C)If the arm of the handle is 42cm long,how far does the hand of the winder travel when bringing the bucket up from the bottom?
My solution so far.
A)1m=100cm
100=tita/360*2*22/7*35/2
tita=327 3/11degree
B) 1rev=360 degree
xrev=327 3/11
=10rev.
Pls kindly help me with the part C
Answers
C) So in effect, the radius of one revolution is 42 cm, and one rotation is 84pi.
Multiply 84pi by the number of rotations
Multiply 84pi by the number of rotations
10REV
not understand
A=1/r=1//0.175
5.714
R=329degree
11/x=0.175/0.42
0.175x=11*0.42/0.175
=26.4m
5.714
R=329degree
11/x=0.175/0.42
0.175x=11*0.42/0.175
=26.4m
Thank you so much the answer is correct.
I do not understand the c part please
thanks guys
i dont understand the b part pls