Asked by james
Water is taken from a well 11m deep in a bucket,the rope winding up to a drum 35cm in diameter.
A)Through what angle does the handle turn in winding up 1m of rope?
B)How many revolutions of the handle does it take to bring the bucket up from the bottom?
C)If the arm of the handle is 42cm long,how far does the hand of the winder travel when bringing the bucket up from the bottom?
My solution so far.
A)1m=100cm
100=tita/360*2*22/7*35/2
tita=327 3/11degree
B) 1rev=360 degree
xrev=327 3/11
=10rev.
Pls kindly help me with the part C
A)Through what angle does the handle turn in winding up 1m of rope?
B)How many revolutions of the handle does it take to bring the bucket up from the bottom?
C)If the arm of the handle is 42cm long,how far does the hand of the winder travel when bringing the bucket up from the bottom?
My solution so far.
A)1m=100cm
100=tita/360*2*22/7*35/2
tita=327 3/11degree
B) 1rev=360 degree
xrev=327 3/11
=10rev.
Pls kindly help me with the part C
Answers
Answered by
Reiny
C) So in effect, the radius of one revolution is 42 cm, and one rotation is 84pi.
Multiply 84pi by the number of rotations
Multiply 84pi by the number of rotations
Answered by
BINI
10REV
Answered by
oboh
not understand
Answered by
Matilda
A=1/r=1//0.175
5.714
R=329degree
11/x=0.175/0.42
0.175x=11*0.42/0.175
=26.4m
5.714
R=329degree
11/x=0.175/0.42
0.175x=11*0.42/0.175
=26.4m
Answered by
[email protected]
Thank you so much the answer is correct.
Answered by
Nina
I do not understand the c part please
Answered by
Ebuka
thanks guys
Answered by
Destiny
i dont understand the b part pls
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