Asked by Kevin
My teacher is an idiot and wont teach our class and im panicking so please help anyone. Given the following equations enthalpy values, determine the heat of reaction (kj) at 298k for the reaction: B2H6(g)+6Cl(g)=2BCl3(g)+6HCl(g)
Answers
Answered by
DrBob222
Do this.
dHrxn = (n*dHformation products) - (n*dHformation reactants)
You can look up the dH formation, usually labeled as delta H<sub>f</sub><sup>o</sup> in your text/notes/on the web.
Post your work if you get stuck.
dHrxn = (n*dHformation products) - (n*dHformation reactants)
You can look up the dH formation, usually labeled as delta H<sub>f</sub><sup>o</sup> in your text/notes/on the web.
Post your work if you get stuck.
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