Asked by Robin
A random sample of 150 pumpkins is obtained and the mean circumference is found to be
45 cm. Assuming that the population standard deviation is known to be 1.8 cm, use a 0.03
significance level to test the claim that the mean circumference of all pumpkins is greater
than 38 cm.
45 cm. Assuming that the population standard deviation is known to be 1.8 cm, use a 0.03
significance level to test the claim that the mean circumference of all pumpkins is greater
than 38 cm.
Answers
Answered by
PsyDAG
Do you have typos?
Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score. Relate to .03.
Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score. Relate to .03.
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