Add -nFEo for Cu^3+ + 2e ==> Cu^+
to -nFEo for Cu^+ ==> Cu^2+ + e
Then total = -nFEo. Solve for Eo
I ran through it quickly and if I didn't punch in the wrong numbers it's about +2.5 v for Cu^3+ + e ==> Cu^2+
Calculate the standard reduction potential for the reaction that coverts Cu3+ to Cu2+. Cu3+ + 2e-> Cu+ E0 =1.28 V
Cu2+ + e-> Cu+ E0 = 0.15V
1 answer