Question
In mixing a weed killing chemical a 40% solution of the chemical is mixed with an 85% solution to get 20 L of a 60% solution. How much of each solution is needed?
Answers
If x at 40%, the rest (20-x) is 85%. So,
.40x + .85(20-x) = .60(20)
.40x + .85(20-x) = .60(20)
amount of 40% stuff --- x L
amount of 85% stuff --- 20-x L
.4x + .85(20-x) = .60x
amount of 85% stuff --- 20-x L
.4x + .85(20-x) = .60x
go with Steve, I messed up, right side is .60(20)
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