Asked by ben
Integral of 1/[x^2(1+x^2)]
Answers
Answered by
bobpursley
I would do this with partial fractions.
Answered by
ben
Please do,I'm waiting...
Answered by
Steve
rather than just sit around waiting, why not actually try it yourself?
1/[x^2(1+x^2)] = 1/x^2 - 1/(1+x^2)
and those are both easy, right?
1/[x^2(1+x^2)] = 1/x^2 - 1/(1+x^2)
and those are both easy, right?
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