Integral of 1/[x^2(1+x^2)]
3 answers
I would do this with partial fractions.
Please do,I'm waiting...
rather than just sit around waiting, why not actually try it yourself?
1/[x^2(1+x^2)] = 1/x^2 - 1/(1+x^2)
and those are both easy, right?
1/[x^2(1+x^2)] = 1/x^2 - 1/(1+x^2)
and those are both easy, right?