Asked by BEN
A private plane traveled from Seattle to a rugged wilderness , at an average speed of 252 mph . on the return trip , the average speed was 180 mph . if the total time was 9 hours how far is Seattle from the wildness
Answers
Answered by
bobpursley
distance=speed*time
d=252*tgoing
d=180*(9-tgoing)
set them equal, solve for time going, then solve for distance.
d=252*tgoing
d=180*(9-tgoing)
set them equal, solve for time going, then solve for distance.
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