Asked by carolin
A2.27g sample of the explosive, nitroglycerin, C3H5(NO3)3, is allowed to explode in a bomb calorimeter at standard conditions. The amount of heat evolved is 15.1 kJ. This explosion of nitroglycerin occurs according to the equation:
2C3H5(NO3)3 (l)⟶6CO2 (g) + 5H2O (l) + 3N2 (g) +1/2O2 (g)
calculate ΔHf for nitroglycerin. (note that the "f" refers to formation)
2C3H5(NO3)3 (l)⟶6CO2 (g) + 5H2O (l) + 3N2 (g) +1/2O2 (g)
calculate ΔHf for nitroglycerin. (note that the "f" refers to formation)
Answers
Answered by
DrBob222
dHrxn = (n*dHf products) - (n*dHf reactants)
Set dHrxn to -15.1 kJ and solve for dHf for nitroglycerin.
Set dHrxn to -15.1 kJ and solve for dHf for nitroglycerin.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.