Question
A2.27g sample of the explosive, nitroglycerin, C3H5(NO3)3, is allowed to explode in a bomb calorimeter at standard conditions. The amount of heat evolved is 15.1 kJ. This explosion of nitroglycerin occurs according to the equation:
2C3H5(NO3)3 (l)⟶6CO2 (g) + 5H2O (l) + 3N2 (g) +1/2O2 (g)
calculate ΔHf for nitroglycerin. (note that the "f" refers to formation)
2C3H5(NO3)3 (l)⟶6CO2 (g) + 5H2O (l) + 3N2 (g) +1/2O2 (g)
calculate ΔHf for nitroglycerin. (note that the "f" refers to formation)
Answers
DrBob222
dHrxn = (n*dHf products) - (n*dHf reactants)
Set dHrxn to -15.1 kJ and solve for dHf for nitroglycerin.
Set dHrxn to -15.1 kJ and solve for dHf for nitroglycerin.