Question

10.6gram of hydrated zinc tetraoxosulphate (vi) on heating to constant mass gave 5.95g of the anhydrous form.Calculate the number of molecules(x) of water of crystalization in the hydrated salt.(zn=65,s=32,o=16,h=1)
10.6-5.95 = g H2O = 4.65
mols H2O = 4.65/18 = ?
mols ZnSO4 = 5.95/molar mass ZnSO4.

Find the ratio of water to 1 mol ZnSO4. The easy way to do that is to divide the mols H2O by mols ZnSO4 and round to a whole number. If I punched in the right numbers on my calculator that shouldb e ZnSO4.7H2O

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