Asked by rishikanta rathore
A commercially. Available. Sample of sulphuric acid is 15percent h2so4 by weight density 1.10gm per ml find molality and normality
Answers
Answered by
DrBob222
The following determines the M and N. If you really want molality repost but m = mols/kg solvent and probably you can do that yourself.
1.10 g/mL x 1000 mL x 0.15 x (1/98) = ?M
Technically one cannot determine the N without knowing the reaction; however, USUALLY, it is M*#H atoms. The reason for that is that one may have two different reactions for H2SO4.
H2SO4 x NaOH ==> NaHSO4 + H2O in which case the N = molar mass/1 or
H2SO4 x 2NaOH ==> Na2SO4 + 2H2O in which case the N = molar mass H2SO4/2
1.10 g/mL x 1000 mL x 0.15 x (1/98) = ?M
Technically one cannot determine the N without knowing the reaction; however, USUALLY, it is M*#H atoms. The reason for that is that one may have two different reactions for H2SO4.
H2SO4 x NaOH ==> NaHSO4 + H2O in which case the N = molar mass/1 or
H2SO4 x 2NaOH ==> Na2SO4 + 2H2O in which case the N = molar mass H2SO4/2
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