Asked by Lily
                Apply the following transformations to this parabola. Y=2(x+3)^2-1
A) reflection in the x-axis, followed by a translation 5 units down.
I got : y = -2(x+3)^2-6
But the answer is y= -2(x+3)^2-4
Why is it -4
And also. How odd you do reflections in the y axis without drawing the graph and just applying to the equation
            
        A) reflection in the x-axis, followed by a translation 5 units down.
I got : y = -2(x+3)^2-6
But the answer is y= -2(x+3)^2-4
Why is it -4
And also. How odd you do reflections in the y axis without drawing the graph and just applying to the equation
Answers
                    Answered by
            MathMate
            
    sx=reflection about the x-axis
(x,y)->(x,-y)
so
(x, 2(x+3)^2-1 ) -> (x, -(2(x+3)^2-1)) = (x, -2(x+3)^2+1)
Now apply the translation of 5 units down to get the answer.
    
(x,y)->(x,-y)
so
(x, 2(x+3)^2-1 ) -> (x, -(2(x+3)^2-1)) = (x, -2(x+3)^2+1)
Now apply the translation of 5 units down to get the answer.
                    Answered by
            Steve
            
    reflection in the y-axis takes
(x,y) -> (-x,y)
Just fold the paper along the y-axis and see what the points do.
    
(x,y) -> (-x,y)
Just fold the paper along the y-axis and see what the points do.
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