Question
A concentration cell consists of two Sn/Sn2+ electrodes. The electrolyte in compartment A is 0.16 M Sn(NO3)2. The electrolyte in B is 0.86 M Sn(NO3)2.
Which electrode is the cathode?
What is the voltage of the cell? (Answer with two significant figures.)
Which electrode is the cathode?
What is the voltage of the cell? (Answer with two significant figures.)
Answers
DrBob222
Ecell = Eocell - (0.05916/n)*log(dilute/concd)
Eocell = 0
Substitute and solve for Ecell.
Eocell = 0
Substitute and solve for Ecell.