Asked by Jessica
Consider the reaction:
M + 2HCl ¨ MCl2 + H2
When 0.85 mol of the metal, M, reacted with an aqueous HCl solution (the HCl is in excess), the temperature of the solution rose because the reaction produced 6795 J of heat. What is ∆H in kJ per mol of M for this reaction? (Hint: Is this reaction exothermic or endothermic?)
M + 2HCl ¨ MCl2 + H2
When 0.85 mol of the metal, M, reacted with an aqueous HCl solution (the HCl is in excess), the temperature of the solution rose because the reaction produced 6795 J of heat. What is ∆H in kJ per mol of M for this reaction? (Hint: Is this reaction exothermic or endothermic?)
Answers
Answered by
DrBob222
The reaction is exothermic and you know that because the temperature of the water increased.
q = 6795 J for 0.85 mol; therefore,
q = 6795/0.85 = dH = ?
Remember to add a - sign since this is exothermic. Also remember to convert from J to kJ.
q = 6795 J for 0.85 mol; therefore,
q = 6795/0.85 = dH = ?
Remember to add a - sign since this is exothermic. Also remember to convert from J to kJ.
Answered by
Anonymous
-7.99
Answered by
Ang
4.7
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.