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A moon rock collected by a U.S. Apollo mission is estimated to be 4.50 billion years old by uranium/lead dating. Assuming that...Asked by josh
A moon rock collected by a U.S. Apollo mission is estimated to be 3.70 billion years old by uranium/lead dating. Assuming that the rock did not contain any lead when it was formed, what is the current mass of 206Pb per 1.185 g of 238U in the rock? The half-life of 238U is t1/2 = 4.47 × 109 years.
How do I find t in the integrated rate law equation. I tried to fiqure this out for hours and im getting to pissed off and I already hate this class so please help.
How do I find t in the integrated rate law equation. I tried to fiqure this out for hours and im getting to pissed off and I already hate this class so please help.
Answers
Answered by
DrBob222
I think t is 3.7E9 years according to the problem.
Here is what I would do.
k = 0.693/t<sub>1/2</sub> and solve for k.
Then ln(No/N) = kt
You know k and t, solve for N/No.
If I understand the problem, the current mass U238 is 1.185g.
So you know No/N and N, solve for No which is the amount of U the sample started with. mass U238 initially - mass U today = mass U decayed and convert that to g Pb today.
mass Pb206 today = mass U decayed x (206/238) = ?
Here is what I would do.
k = 0.693/t<sub>1/2</sub> and solve for k.
Then ln(No/N) = kt
You know k and t, solve for N/No.
If I understand the problem, the current mass U238 is 1.185g.
So you know No/N and N, solve for No which is the amount of U the sample started with. mass U238 initially - mass U today = mass U decayed and convert that to g Pb today.
mass Pb206 today = mass U decayed x (206/238) = ?
Answered by
josh
Thank you DrBob, you saved a couple hours of my life.
Answered by
j
Thank god for dr bob
Answered by
df
wtf dr bob
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