Asked by lawerence
In 20 s, the concentration of NO2 decreases from 450 mM to 320 mM in the reaction
2 NO2 --> 2 NO + O2
(a) Determine the rate of reaction of NO2
(b) Determine the rate of formation of O2
(c) What is the unique rate of the reaction?
2 NO2 --> 2 NO + O2
(a) Determine the rate of reaction of NO2
(b) Determine the rate of formation of O2
(c) What is the unique rate of the reaction?
Answers
Answered by
DrBob222
You would do well to keep the same screen name. We can help better if you do that.
rate = 1/2*d(NO2)/dT
d(NO2) = 450-320 = 130
dT = 20
rate formation O2 is 2x rate NO2 decomposition
rate = 1/2*d(NO2)/dT
d(NO2) = 450-320 = 130
dT = 20
rate formation O2 is 2x rate NO2 decomposition
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