Asked by Sara
In an experiment, 13g of methanol and 11 g of carbon monoxide were placed in a reaction vessel. Given the following reaction
C:12.0 amu O:16.0 amu H:1.0 amu
CH3OH + CO --> HC2H3O2
1 What is the theoretical yield of acetic acid?
2 If the actual yield of acetic acid is 19.1 g, what is the percent yield?
C:12.0 amu O:16.0 amu H:1.0 amu
CH3OH + CO --> HC2H3O2
1 What is the theoretical yield of acetic acid?
2 If the actual yield of acetic acid is 19.1 g, what is the percent yield?
Answers
Answered by
DrBob222
See your previous problem. This is not a LR problem BUT in the previous problem you calculated TWO problems like this while this is just one of those problems. The theoretical yield is the mols produced by that one calculation. We'll call that TY. The actual yield (AY) is 19.2g.
% yield = (AY/TY)*100 = ?
% yield = (AY/TY)*100 = ?
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