Asked by james
6cm diameter discs are cut from a sheet 130cm long and 70cm wide.(a)How many discs can be cut in this way (b) what area of the sheet is wasted?
(My working so far).
Area of rectangle=L*B
130*70=9100cm^2
area of circle=22/7 *(6/2)^2=28.286cm^2
(a)no of discs cut=9100/28.286=321
pls help with the (b) part of the question.which is: what area of the sheet is wasted?
(My working so far).
Area of rectangle=L*B
130*70=9100cm^2
area of circle=22/7 *(6/2)^2=28.286cm^2
(a)no of discs cut=9100/28.286=321
pls help with the (b) part of the question.which is: what area of the sheet is wasted?
Answers
Answered by
Steve
just subtract what was used from the original amount:
9100 - 321*28.286
However, that assumes that all the leftover parts could be combined to form new circles; not very likely. A better way to look at it is to decide how many rows and columns of discs could be cut.
130/6 = 21.67
70/6 = 11.67
So, you have 21 rows of 11 discs, or 231 discs
Now the wastage is 9100 - 231*28.286
In fact, however, there are better ways of packing the discs onto the sheet than a square lattice, but that gets quite complicated.
9100 - 321*28.286
However, that assumes that all the leftover parts could be combined to form new circles; not very likely. A better way to look at it is to decide how many rows and columns of discs could be cut.
130/6 = 21.67
70/6 = 11.67
So, you have 21 rows of 11 discs, or 231 discs
Now the wastage is 9100 - 231*28.286
In fact, however, there are better ways of packing the discs onto the sheet than a square lattice, but that gets quite complicated.
Answered by
sisa
248 322.794
Answered by
Olukitibi Heritage
I m not satisfied with the answers.
Answered by
YUSUF aaa
Am not satisfied with the answers
Answered by
YUSUF aaa
Answer to the second question B
Answered by
Egharevba osas
Explain as if you teach a SS1 child it’s hard to comprehend
Answered by
Seyi
Wrong answer
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.