Asked by Kyle
Answer the following questions below that go with the following: Let's say that a locker combination lock uses numbers 0 through 39 for a 3 digit combination.
1.) Exactly how many combinations are possible if NO digit may be repeated? And how many combinations are possible if digits may be repeated?
1.) Exactly how many combinations are possible if NO digit may be repeated? And how many combinations are possible if digits may be repeated?
Answers
Answered by
Reiny
so there are 40 numbers to pick from.
first choice -- 40
2nd choice -- 39
3rd choice -- 38
what is 40*39*38 ?
first choice -- 40
2nd choice -- 39
3rd choice -- 38
what is 40*39*38 ?
Answered by
Betty
59280?
Answered by
Reiny
yes,
remember there were actually two questions.
Which of the two did we answer, and how would you do the other one?
remember there were actually two questions.
Which of the two did we answer, and how would you do the other one?
Answered by
Kyle
We did the question (And how many combinations are possible if digits may be repeated?)
Answered by
Reiny
yes, the first one.
How would you do the second one ?
How would the solution change ?
How would you do the second one ?
How would the solution change ?
Answered by
Betty
Would the solution be just 40?
Answered by
Reiny
Betty ? Kyle ? , please stick to one name
No, how can it be simply 40 when the first answer was 59280 ??
You are just guessing and hope that I will give you the solution.
Look at my solution for the first one, and tell me why my second multiplier is only 39 instead of 40 and why my third multiplier is only 38 ??
No, how can it be simply 40 when the first answer was 59280 ??
You are just guessing and hope that I will give you the solution.
Look at my solution for the first one, and tell me why my second multiplier is only 39 instead of 40 and why my third multiplier is only 38 ??
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