Question
A uniform plank of seesaw is 5meter long.a boy weighing40kgf sits 1.5meter from the one end.what will be the distance of a girl weighing 25kgf sit at other end,so as to balance the seesaw.
Answers
Henry
Distance from each end to the center =
5/2 = 2.5 m.
2.5 - 1.5 = 1.0 m from center.
40*1 = 25*d
d = 1.6 m from center = 0.9 m from the
end.
5/2 = 2.5 m.
2.5 - 1.5 = 1.0 m from center.
40*1 = 25*d
d = 1.6 m from center = 0.9 m from the
end.