Asked by Anonymous
How do I solve this?
A satellite has a mass of 5949 kg and is in a circular orbit 4.07 × 105 m above the surface of a planet. The period of the orbit is 1.9 hours. The radius of the planet is 4.55 × 106 m. What would be the true weight of the satellite if it were at rest on the planet’s surface?
A satellite has a mass of 5949 kg and is in a circular orbit 4.07 × 105 m above the surface of a planet. The period of the orbit is 1.9 hours. The radius of the planet is 4.55 × 106 m. What would be the true weight of the satellite if it were at rest on the planet’s surface?
Answers
Answered by
bobpursley
mw^2(r+h)_=GMm/(h+r)
w^2* (h+r)^2=GM
w=2PI/Period, you have h+r (add them).
So what is GMm/r^2? Now you can compute..
weight= (2PI/Period)^2*(h+r)^2*m/r^2
w^2* (h+r)^2=GM
w=2PI/Period, you have h+r (add them).
So what is GMm/r^2? Now you can compute..
weight= (2PI/Period)^2*(h+r)^2*m/r^2
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