Question

For the quadratic function f(x) = 2x^2 - 16x + 27
The Vertex = ___?

f(x) attains a maximum minimum value of ___?

The axis of symmetry is___?

The x-intercepts are___? and The y-intercept is ____?

Answer 1

x of the vertex is -b/(2a) -----> good formula to memorize
= -(-16)/(4) = 4
f(4) = ....

so now you have the vertex.
easy to read off the max/min and the axis of symmetry.

for x intercept let y = 0 in y = 2x^2 - 16x + 27
for y intercept let x = 0 in y = 2x^2 - 16x + 27

confirm my looking at the graph:
http://www.wolframalpha.com/input/?i=y+%3D+2x%5E2+-+16x+%2B+27