Asked by Zubair
mr. mike invested two sums of money on simple interest. the fist was $2200 invested at 8% per annum and the second $1960 at 10% per annum. the sums were allowed to frow till bothe amounted to the same figure. in how many years did this happaended and what was the final amount?
Answers
Answered by
Steve
You want x, where
2200(1+.08x) = 1960(1+.10x)
2200(1+.08x) = 1960(1+.10x)
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