Asked by Anonymous

Given the relationship 2x^2 + y^3 =10, with y > 0 and dy, dt = 3 units/min., find the value of dx, dt at the instant x = 1 unit.
Answered by Anonymous
Given the relationship 2x^2 + y^3 =10, with y > 0 and dy/dt = 3 units/min., find the value of dx/ dt at the instant x = 1 unit.
Answered by Steve
4x dx/dt + 3y^2 dy/dt = 0

Now just plug in your values and solve for dx/dt.
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