The problem tells you %Cl = 8.43%. Is this gravimetric analysis to check that number?
Convert 0.0831g AgCl to Cl. That is easiest done by 0.0831 x (atomic mass Cl/molar mass AgCl) = g Cl
Then %Cl = [(mass Cl/mass sample)]*100 =
an organic pesticide (mw 183.7) is 8.43% cl. a 0.627g sample containing the pesticide plus inert material containing no chloride was decomposed with metallic sodium in alcohol. the liberated chloride ion was precipitated as agcl weighing 0.0831g. calculate the percentage of pesticide in the sample.
2 answers
2. An organic pesticide has F. wt: 183.7 g/mol.A 0.627g sample containing the pesticide and inert material containing no Cl was decomposed with metallic sodium in alcohol. The liberated chloride ion was precipitated as AGCI weighing 0.0831g. calculate the percentage of cr ions in pesticide sample.