Question
A gun converts 200J of stored energy into kinetic energy of the 0.02kg bullet. What is the speed of the bullet as it leaves the gun? If the gun is fired straight up how high will the bullet go?
Answers
a. KE = 0.5*M*Vo^2
KE = 200 J.
M = 0.02 kg
Solve for Vo, the initial velocity.
b. M*g*h = 200
M = 0.02 kg
9 = 9.8 m/s^2
Solve for h.
KE = 200 J.
M = 0.02 kg
Solve for Vo, the initial velocity.
b. M*g*h = 200
M = 0.02 kg
9 = 9.8 m/s^2
Solve for h.