Asked by Dom
The bird perched on the swing has a mass of 48.0 g, and the base of the swing has a mass of 159 g. The swing and bird are originally at rest, and then the bird takes off horizontally at 1.20 m/s. How high will the base of the swing rise above its original level? Disregard friction.
Answers
Answered by
Damon
first use conservation of momentum to get swing speed at bottom
Vswing = Vbird (Mass bird/Mass swing)
then
m g h = (1/2) m Vswing^2
or
h = Vswing^2/(2 *9.81)
Vswing = Vbird (Mass bird/Mass swing)
then
m g h = (1/2) m Vswing^2
or
h = Vswing^2/(2 *9.81)
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