Asked by Adil
90.0g of copper (c=390J/kg*oC) at 80.0°C are added to 270g of water at 20.0°C. What is the final temperature of the mixture?
Answers
Answered by
bobpursley
the sum of heats gained is zero. Heat gained = mass*c*(Tf-Ti)
Heatgainedcopper+heatgainedwater=0
90*ccopper*(Tf-80)+270*cwater*(Tf-20)=0
solve for Tf
Heatgainedcopper+heatgainedwater=0
90*ccopper*(Tf-80)+270*cwater*(Tf-20)=0
solve for Tf
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