Question
how do you eliminate the parameters for x=1-t^2 and y=1+t?
Answers
Damon
t^2 = 1-x
t = y-1 so t^2 = y^2-2y+1
so
y^2-2y+1 = 1 - x
t = y-1 so t^2 = y^2-2y+1
so
y^2-2y+1 = 1 - x
JK
so its y^2-2y=x
not solving for y?
not solving for y?
Damon
y^2 - 2 y = -x
You were asked to eliminate the parameter t, not to solve for y. However I do not know the traditions of your particular group :)
You were asked to eliminate the parameter t, not to solve for y. However I do not know the traditions of your particular group :)
JK
find directrix of 1/1-cos theta