Asked by John
How many liters of chlorine as can be produced when 1.96 L of HCl react with excess O2 at STP
Show Work
A.0.49L
B.0.98L
C.1.96L
D.3.92L
Show Work
A.0.49L
B.0.98L
C.1.96L
D.3.92L
Answers
Answered by
DrBob222
You work this exactly like the problem with glucose and oxygen.
1. Write and balance the equation.
2. Use the coefficients to convert mols of what you have to mols of what you want.
3. Convert mols of what you want to either grams or volume.
g = mols x molar mass
volume = mols x 22.4 L/mol if at STP or
PV = nRT if not at STP.
1. Write and balance the equation.
2. Use the coefficients to convert mols of what you have to mols of what you want.
3. Convert mols of what you want to either grams or volume.
g = mols x molar mass
volume = mols x 22.4 L/mol if at STP or
PV = nRT if not at STP.
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