Asked by Alexis
The ordinate of a point P is twice the abscissa. This point is equidistant from (-3, 1) and (8,-2). Find the coordinates of P.
Answers
Answered by
Steve
P = (x,2x)
(x+3)^2 + (2x-1)^2 = (x-8)^2 + (2x+2)^2
...
(x+3)^2 + (2x-1)^2 = (x-8)^2 + (2x+2)^2
...
Answered by
Shasha Ramiro
P = (x,2x)
(x+3)^2 + (2x-1)^2 = (x-8)^2 + (2x+2)^2
(x+3)^2 + (2x-1)^2 = (x-8)^2 + (2x+2)^2
Answered by
Christ
No
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