Question

The ordinate of a point P is twice the abscissa. This point is equidistant from (-3, 1) and (8,-2). Find the coordinates of P.

Answer 1

P = (x,2x)

(x+3)^2 + (2x-1)^2 = (x-8)^2 + (2x+2)^2

...

Answer 2

P = (x,2x)

(x+3)^2 + (2x-1)^2 = (x-8)^2 + (2x+2)^2

Answer 3

No