Asked by Alexis

The ordinate of a point P is twice the abscissa. This point is equidistant from (-3, 1) and (8,-2). Find the coordinates of P.

Answers

Answered by Steve
P = (x,2x)

(x+3)^2 + (2x-1)^2 = (x-8)^2 + (2x+2)^2

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Answered by Shasha Ramiro
P = (x,2x)

(x+3)^2 + (2x-1)^2 = (x-8)^2 + (2x+2)^2

Answered by Christ
No
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