Asked by david
Determine the volumes of 0.10 M CH3COOH and 0.10 M CH3COONa required to prepare 10.0 mL of buffer of each of the following pH values?
a. Ph 3.7
b. pH 5.7
C. pH 5.7
I just need to see how to do one of them and I'll understand how to do the rest.
a. Ph 3.7
b. pH 5.7
C. pH 5.7
I just need to see how to do one of them and I'll understand how to do the rest.
Answers
Answered by
DrBob222
Plug and chug into the HH equation.
These problelms, where no concentration is given for the buffer, is a wide open problem with no restrictions. Here is what you do.
Let x volume(in mL) CH3COONa and 10-x = volume in mL of CH3COOH.
pKa CH3COOH is about 4.74 but you need to use the value in your text.
3.7 = 4.74 + log (0.1x)/0.1(10-x)
Solve for x ad 10-x
These problelms, where no concentration is given for the buffer, is a wide open problem with no restrictions. Here is what you do.
Let x volume(in mL) CH3COONa and 10-x = volume in mL of CH3COOH.
pKa CH3COOH is about 4.74 but you need to use the value in your text.
3.7 = 4.74 + log (0.1x)/0.1(10-x)
Solve for x ad 10-x
Answered by
micheal
1.5
Answered by
Jacqueline Griffith
pH = pka + log [base CH3COONa]/[acid CH3COOH]
3.7 = 4.7 + log [base]/[acid]
alegbra to remove 4.7 from both sides
-1.0 = log [base]/[acid]
log= 10^x so alegbra to remove 10^x
10^-1 = [base]/[acid] or 0.10 = [base]/[acid]
1 ml for base added to 9 ml of acid
3.7 = 4.7 + log [base]/[acid]
alegbra to remove 4.7 from both sides
-1.0 = log [base]/[acid]
log= 10^x so alegbra to remove 10^x
10^-1 = [base]/[acid] or 0.10 = [base]/[acid]
1 ml for base added to 9 ml of acid
Answered by
harrhy
2.4
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