Asked by TayB
Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it.
lim x→3 (x^2+3x−18)/(x−3)
lim x→3 (x^2+3x−18)/(x−3)
Answers
Answered by
Steve
how about I do this one, and you at least try on the others?
x^2+3x-18 = (x+6)(x-3)
So, everywhere except at x=3, f(x) = x+6
That means we expect the limit to be 3+6=9
Using the suggestion, the limit is
(2x+3)/1 = 2*6+3 = 9
x^2+3x-18 = (x+6)(x-3)
So, everywhere except at x=3, f(x) = x+6
That means we expect the limit to be 3+6=9
Using the suggestion, the limit is
(2x+3)/1 = 2*6+3 = 9
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.