Asked by braeden
When 6 liter of nitrogen gas reacts with 18
liters of hydrogen gas at constant temperature
and pressure, how many liters of ammonia gas
will be produced?
liters of hydrogen gas at constant temperature
and pressure, how many liters of ammonia gas
will be produced?
Answers
Answered by
DrBob222
N2 + 3H2 ==> 2NH3
When gases are involved one may use a shortcut and use L as if they were mols.
This is a limiting reagent problem (LR) and you know that because amounts are given for BOTH reactants.
I do these the long way.
How much NH3 can be produced from 6 L N2 and all of the H2 needed. That is
6L x (2 mol NH3/1 mol H2) = 12 L NH3.
How much NH3 can be produced from 18 L H2 and all of the N2 needed. That is
18 x (2 mols NH3/3 mols H2) = 12 L NH3.
The numbers are the same so you will have 18 L NH3 produced.
When gases are involved one may use a shortcut and use L as if they were mols.
This is a limiting reagent problem (LR) and you know that because amounts are given for BOTH reactants.
I do these the long way.
How much NH3 can be produced from 6 L N2 and all of the H2 needed. That is
6L x (2 mol NH3/1 mol H2) = 12 L NH3.
How much NH3 can be produced from 18 L H2 and all of the N2 needed. That is
18 x (2 mols NH3/3 mols H2) = 12 L NH3.
The numbers are the same so you will have 18 L NH3 produced.
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