prob(Saturday) = 1/7
prob(not Saturday) = 6/7
a) prob(as stated) = C(15,4) (1/7)^4 (6/7)^11
= appr .1043
b) prob(at least 2 Saturdays)
---> 1 - (no Saturday + 1 Saturday)
= 1 - ( C(15,0) (1/6)^0 (6/7)^15 + .....)
I will let you finish that one
a probability that new years is on a Saturday in a randomly chosen year is 1/7. 15 years are chosen randomly.find the probability that
1. exactly four of these years have new years day on a Saturday
2. at least 2 of these years have new years day on a Saturday
1 answer