Asked by Vicky
what is the global maximum of the parabola
y= -x^2 -12x +4
y= -x^2 -12x +4
Answers
Answered by
Steve
you should recall that for
y = ax^2+bx+c
the vertex is at x = -b/2a
So, figure that for x, then evaluate y there. Since this parabola opens downward, its vertex is the maximum value.
y = ax^2+bx+c
the vertex is at x = -b/2a
So, figure that for x, then evaluate y there. Since this parabola opens downward, its vertex is the maximum value.
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