Asked by marry
The 5th term of an Arithmetic Progression is 8 and the 12th term is 50. Determine the sequence
Answers
Answered by
Steve
d = (T12-T5)/(12-5) = (50-8)/7 = 6
T5 = a+4*6=8, so a = -16
Thus, the sequence is
-16 -10 -4 2 8 ...
T5 = a+4*6=8, so a = -16
Thus, the sequence is
-16 -10 -4 2 8 ...
Answered by
vannu
In the Arithmetic progression the 5th term is 21 and 12 term is 49
Determine
A)Common difference "d" and the first term
B) fifteen term (15th) term T15 and U 15
C) sum of first s15
Determine
A)Common difference "d" and the first term
B) fifteen term (15th) term T15 and U 15
C) sum of first s15
Answered by
Britney
Find the fifth term of the sequence -3,6-12....
Answered by
Anonymous
In an arithmetic sequence, if the 5th term is 7 and the 9th term is -9, find the 12th term.
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