Question

A galvanic cell is composed of these two half-cells, with the standard reduction potentials shown:

Cu2+(aq) + 2 e- ---->Cu(s)
+0.34volt

Cd2+(aq) + 2 e- ---->Cd(s)
-0.40volt
What is the standard free energy change for the cell reaction of this galvanic cell?
Reverse the Cd half cell and add to the Cu half cell as written. Calculate Eo cell.
Then dG = -nFEcell.
n is 2 and F is 96,485.
It would be more than nice if you didn't switch screen names.

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