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Use Gaussian elimination to find the complete solution to the system of equations, or state that none exists. Show your work. 4...Asked by Ciara
Use Gaussian elimination to find the complete solution to the system of equations, or state that none exists. Show your work.
4x-y+3z = 12
x+4y+6z =-32
5x+3y+9z = 20
4x-y+3z = 12
x+4y+6z =-32
5x+3y+9z = 20
Answers
Answered by
Steve
Enter your coefficients here and see all the details:
http://www.gregthatcher.com/Mathematics/GaussJordan.aspx
http://www.gregthatcher.com/Mathematics/GaussJordan.aspx
Answered by
Ciara
I don't know how to use that
Answered by
Ciara
When I do it , it says Im wrong
Answered by
Steve
well, when I do it, it says I'm right, so why don't you show your work here and we can see how things go?
Answered by
Ciara
How did you do it ? what do you put in the boxes ?
Answered by
Ciara
I actually have to show my work , But I need help with this
Answered by
Steve
I'll get you started. But you clearly need to study the examples in your text. Or, just do a google and you will find lots of examples online.
You start with your matrix of coefficients:
4 -1 3 | 12
1 4 6 | -32
5 3 9 | 20
You want to work things so that you have a final matrix with the left side looking like
1 0 0
0 1 0
0 0 1
And then the 4th column will have the values of the variables.
So, starting with
4 -1 3 | 12
1 4 6 | -32
5 3 9 | 20
if you multiply the 2nd row by 4 you have
4 -1 3 | 12
4 16 24 | -128
5 3 9 | 20
Now if you subtract the top row from the 2nd row, you have
4 -1 3 | 12
0 17 21 | -140
5 3 9 | 20
Now multiply the 3rd row by 4 and you have
4 -1 3 | 12
0 17 21 | -140
20 12 36 | 80
Now subtract the top row from the 3rd row and you have
4 -1 3 | 12
0 17 21 | -140
0 17 21 | 20
Woah! At this point you have
17y+21z = -140
17y+21z = 20
so there is no solution, since -140 ≠ 20
You really should go back to the web site and play around with some numbers just to get used to how it works.
You start with your matrix of coefficients:
4 -1 3 | 12
1 4 6 | -32
5 3 9 | 20
You want to work things so that you have a final matrix with the left side looking like
1 0 0
0 1 0
0 0 1
And then the 4th column will have the values of the variables.
So, starting with
4 -1 3 | 12
1 4 6 | -32
5 3 9 | 20
if you multiply the 2nd row by 4 you have
4 -1 3 | 12
4 16 24 | -128
5 3 9 | 20
Now if you subtract the top row from the 2nd row, you have
4 -1 3 | 12
0 17 21 | -140
5 3 9 | 20
Now multiply the 3rd row by 4 and you have
4 -1 3 | 12
0 17 21 | -140
20 12 36 | 80
Now subtract the top row from the 3rd row and you have
4 -1 3 | 12
0 17 21 | -140
0 17 21 | 20
Woah! At this point you have
17y+21z = -140
17y+21z = 20
so there is no solution, since -140 ≠ 20
You really should go back to the web site and play around with some numbers just to get used to how it works.
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