Question
the isotope has a very short life of 13 half-life days.
estimate the percentage of the original amount of the isotope released by the explosion that remains 3 days after the explosion?
estimate the percentage of the original amount of the isotope released by the explosion that remains 3 days after the explosion?
Answers
after t days, the amount left is
(1/2)^(t/13)
So, after 3 days, the amount left is
(1/2)^(3/13) = .852 = 85.2%
(1/2)^(t/13)
So, after 3 days, the amount left is
(1/2)^(3/13) = .852 = 85.2%
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