Asked by jaimi
How many kg of wet NaOH containing 12% water are required to prepare 60 litre of 0.5N solution?
Answers
Answered by
DrBob222
Let's assume for the moment the water is not there.
How many mols do we want. That is M x L = mols = 0.5 x 60 = ? (I've used molarity since mols and equivalents for NaOH are the same).
How many grams is that?
grams = mols x molar mass IF IT WERE PURE STUFF BUT IT'S ONLY 100-12 = 88% NaOH. Therefore, we need grams from above/0.88 = grams of the wet stuff.
How many mols do we want. That is M x L = mols = 0.5 x 60 = ? (I've used molarity since mols and equivalents for NaOH are the same).
How many grams is that?
grams = mols x molar mass IF IT WERE PURE STUFF BUT IT'S ONLY 100-12 = 88% NaOH. Therefore, we need grams from above/0.88 = grams of the wet stuff.
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