If you have a spinner with six spaces each with a letter P,U,I,O,E,N and you spin the spinner twice what is the P(vowel, then P)?

Question

A.1/3
B.1/9
C.5/6
D.5/12
Is the answer D?

Answer 1

The answer is B.

Answer 2

Explanation:

First time: 3/6 Which is 1/2 to land on a vowel.

Second time, 1/6 to land on P

(1/6) (1/2)

Answer 3

Yes it's B. This is another example of conditional probability.

Note that there are four vowels here: U, I, O, E. And there are six letters total. So,
P(vowel) = 4/6

Then you spin again. The probability of getting a P:
P(P) = 1/6

Thus,
P(vowel, then P) = 4/6 * 1/6 = 4/36 = 1/9

hope this helps~ `u`

Answer 4

Thanks Jai for correcting me. I obviously read that too fast. Yes. All seems correct.

Answer 5

Thank you both for the help.