Asked by hira

Only 6M KOH was present on the reagent shelf- there was no 6M NaOH. explain what effect this substitution has on the test for the presence of the ammonium ion?
Answered by DrBob222
I don't think it has any effect; at least I don't know about it if it does. The test is to add strong base to an ammonium salt and it releases NH3 gas. Both KOH and NaOH are strong bases.