Question
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Write the balanced equation, with the enthalpy component, for the rusting process, given that Hf for iron and oxygen is 0 and Hf for ferric oxide is -826 kJ/mol.
4 Fe (s) + 3 O2 (g) --------> 2 Fe2O3 (s)
You need to add the heat one of three ways.
4 Fe (s) + 3 O2 (g) --------> 2 Fe2O3 (s) + <b>heat</b> or
4 Fe (s) + 3 O2 (g) --------> 2 Fe2O3 (s) <b> delta H = -826 kJ/mol</b> or
4 Fe (s) + 3 O2 (g) --------> 2 Fe2O3 (s) <b>delta H = -3304 kJ</b>
I don't know your teacher's preference
Write the balanced equation, with the enthalpy component, for the rusting process, given that Hf for iron and oxygen is 0 and Hf for ferric oxide is -826 kJ/mol.
4 Fe (s) + 3 O2 (g) --------> 2 Fe2O3 (s)
You need to add the heat one of three ways.
4 Fe (s) + 3 O2 (g) --------> 2 Fe2O3 (s) + <b>heat</b> or
4 Fe (s) + 3 O2 (g) --------> 2 Fe2O3 (s) <b> delta H = -826 kJ/mol</b> or
4 Fe (s) + 3 O2 (g) --------> 2 Fe2O3 (s) <b>delta H = -3304 kJ</b>
I don't know your teacher's preference