Asked by Jamie lee
It has been determined that the body can generate 5500 kJ of energy during one hour of strenuous exercise. Perspiration is the body's mechanism for eliminating this heat. How many liters of water would have to be evaporated through perspiration to rid the body of the heat generated during two hours of exercise? (The heat of vaporization of water is 40.6 kJ/mol. Assume the density of water is 1.000 g/mL)
Answers
Answered by
DrBob222
5500 kJ.
40.6 kJ/mol x # mol = 5500 kJ.
Solve for mols H2O
Convert mols H2O to grams.
Convert, using density, grams H2O to L H2O.
40.6 kJ/mol x # mol = 5500 kJ.
Solve for mols H2O
Convert mols H2O to grams.
Convert, using density, grams H2O to L H2O.
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