An aqueous solution of a monoprotic acid is prepared. This acid is known to have a pKa of 8.6. If the acid is 37.5% ionized when in solution, what is the pH of the solution?

Not really sure where to start with this question? Thanks in advance

2 answers

pKa = -log Ka. Solve for Ka.

Then..........HA ==> H^+ + A^-
I.............1.......0.....0
C...........-.375...0.375..0.375
E...........0.625...0.375..0.375

Substitute the E line into the Henderson-Hasselback equation and solve for pH.
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