Asked by Bafana
A flying bat emits squeaks at a frequency of 80 MHz, if a stationary observer picks up the frequency of the squeaks as 78 MHz, is the bat moving towards or away from the listener? Determine the speed of the bat.
Answers
Answered by
Henry
Fb = 80 kHz = Freq. emitted by the bat.
Fh = 78 kHz = Freq. heard.
Vs = 343 m/s = Velocity of sound in air.
a. The bat is moving away.
b. Fh = (Vs-Vr)/(Vs+Vb) * Fb = 78 kHz
(343-0)/(343+Vb) * 80 = 78
Solve for Vb, the velocity of the bat.
Fh = 78 kHz = Freq. heard.
Vs = 343 m/s = Velocity of sound in air.
a. The bat is moving away.
b. Fh = (Vs-Vr)/(Vs+Vb) * Fb = 78 kHz
(343-0)/(343+Vb) * 80 = 78
Solve for Vb, the velocity of the bat.
There are no AI answers yet. The ability to request AI answers is coming soon!