Asked by Camille

three 20 kilo ohms Resistors R1, R2, and R3 are in Series across an applied voltage of 120 V. What is the voltage drop across each resistor.

Answers

Answered by MathMate
Resistance across resistors in <i>series</i>
= R1+R2+R3

Voltage across each resistor is proportional to the fraction of each over the total.

For <b>example</b>,
resistors R1=2,R2=1,R3=3, ohms are connected in <i>series</i> and subject to a voltage of 12 volts,
Resistance of resistors in series
R=R1+R2+R3=2+1+3=6

voltage drops
V1=(R1/R)*12=(2/6)*12=4 volts
V2=(R2/R)*12=(1/6)*12=2 volts
V3=(R3/R)*12=(3/6)*12=6 volts
Check: total = 4+2+6=12 volts, ok.
Answered by Henry
Rt = R1+R2+R3 = 20k + 20k + 20k = 60k Ohms. = Total resistance.

I = E/Rt = 120/60k = 2 mA(milliamps).

V1 = V2 = V3 = I*R1 = 2 * 20k = 40 Volts
Therefore, the voltage across each resistor is 40 Volts.
Answered by Camille
Thanks.. :)
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